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Originally Posted by Jim-mi
Paul, what you are close to is what is called "Swept area"
100 foot long blades have a very LARGE "swept area"
Think I'll quit and leave it at that. I'm not in the mood to type in two pages on "swept area" and all the other blade stuff.
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Lets see if I get this right, Jim. With 100 baldes it would take a large hub for them. Lets say 5 feet. Wheather it had 2 or more blades the swept area would still be a 205 feet diameter circle or 33,006.435 square feet.
205 squared = 42025 x .7854 = swept area
I think I am right, any way.
Rambler, I have wondered if you couldn't build an hour glass shaped funnel, with the rear section larger than the intake , well try to picture this.
Say a mill with a 20' diameter set of blades like the old timers used for pumping water. More aerodynamic, of course, with an intake on the funnel about 40 feet wide and the exhaust end of it about 50 or 60 feet to create a vacuum on the back side to suck the disturbed air flow out at a faster pace.
If I ever get rich, (LMAO), I would like to try it.
You would only have blades that were 8.5 to 9 feet, which would be less expensive than larger blades because of the balanceing and strenght required, and you would only have about 315 feet of swept area, but you would be catching over 1200 feet of air flow.
It seems to me that it would be like a hose pipe with a nossle on it, and create more pressure and a faster airflow on the blades, making them more powerfull in low wind areas.
That is just an idea I have toyed with, because we don't have a lot of sustained wind where I live.
Stupid idea, huh??
Dennis