
10/20/04, 10:13 AM
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Join Date: Aug 2004
Location: Florida
Posts: 18
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LEDs require about 20-30 milliamps of current to light, and cause a voltage drop of approx. 2 volts. Using Ohms Law, V = I*R, you can solve for the current limiting resistor that you need. R = ( 9 Volts - 2 Volts ) / 0.025 Amps = 280 Ohms. Any resistor value in that ballpark ought to work for you. LEDs are tolerant of overcurrent, but too much will shorten the diode's operating life if it doesn't fry the device outright.
A 9 Volt battery is very inefficient for lighting one diode, since most of the power is dissipated by the resistor. A couple of AAs or AAAs in series (3V) would do the job just fine, with a smaller resistor of course (40 Ohms).
I bought mine from Digikey online two years ago. Prices have fallen substantially since then. Ebay has hundreds of options, for a much better price. Just about all colors (wavelengths), intensities and fields of view are available, but the green, blue, white and ultraviolet ones will cost a lot more than the red, yellow and orange colors.
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